-16+2x^2+7x=1

Solution for -16+2x^2+7x=1 equation:

-16+2x^2+7x=1

We move all terms to the left:

-16+2x^2+7x-(1)=0

We add all the numbers together, and all the variables

2x^2+7x-17=0

a = 2; b = 7; c = -17;
Δ = b2-4ac
Δ = 72-4·2·(-17)
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{185}}{2*2}=\frac{-7-\sqrt{185}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{185}}{2*2}=\frac{-7+\sqrt{185}}{4}
$